OFFSET
1,1
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
FORMULA
Find integral quotients of products of consecutive primes divided by their sum.
EXAMPLE
a(2) = 5 because it is the last consecutive prime in the run 2*3*5 = 30 and 2+3+5 = 10; since 30/10 = 3, it is the first integral quotient.
MATHEMATICA
seq = {}; sum = 0; prod = 1; p = 1; Do[p = NextPrime[p]; prod *= p; sum += p; If[Divisible[prod, sum], AppendTo[seq, p]], {200}]; seq (* Amiram Eldar, Nov 02 2020 *)
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Enoch Haga, May 28 2008
EXTENSIONS
Edited by R. J. Mathar, Jun 09 2008
a(1) added by Amiram Eldar, Nov 02 2020
STATUS
approved