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A140460
a(0) = 2; thereafter a(n) = smallest integer not a multiple of an earlier terms nor a sum of two earlier terms.
2
2, 3, 7, 11, 17, 23, 29, 37, 41, 47, 53, 59, 65, 71, 79, 83, 89, 95, 101, 107, 113, 125, 131, 137, 149, 155, 163, 167, 173, 179, 191, 197, 211, 215, 223, 227, 233, 239, 247, 251, 257, 263, 269, 277, 281, 293, 305, 311, 317, 331, 335
OFFSET
0,1
COMMENTS
Note that the first composite value is a(12) = 65 = 5 * 13, since 5 and 13 are first two primes sieved out of the sequence. Similarly, the second composite value is a(17) = 95 = 5 * 19, since 5 and 19 are first and third primes sieved out of the sequence. - Jonathan Vos Post, Jul 27 2008
LINKS
PROG
(C) void sieve(){ const int first = 2; const int max = 10000; bool member[max]; for(int i = first; i < max; ++i){ member[i] = true; } for(int i = first; i < max; ++i){ if(member[i]){ for(int x = i + i; x < max; x += i){ member[x] = false; } for(int j = first; j < i; ++j){ if(member[j] && i + j < max){ member[i + j] = false; } } } } int num = 0; for(int i = first; i < max; ++i){ if(member[i]){ printf("%i, ", i); num += 1; } } printf(" num = %i ", num); }
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Russell Y. Webb (r.webb(AT)elec.canterbury.ac.nz), Jul 22 2008
STATUS
approved