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%I #13 Jan 16 2022 00:54:53
%S 7,31,181,1261,10081,90721,907201,9979201,119750401,1556755201,
%T 21794572801,326918592001,5230697472001,88921857024001,
%U 1600593426432001,30411275102208001,608225502044160001,12772735542927360001
%N a(n) = (n!+4)/4.
%C Maximal solution for x such that x^2-y^2 = n! (because ((n! + 4)/4)^2 - ((n! - 4)/4)^2 = n! ). [Artur Jasinski, Mar 31 2012]
%t Table[(n! + 4)/4, {n, 4, 30}]
%o (PARI) a(n)=n!/4+1 \\ _Charles R Greathouse IV_, Jun 20 2012
%K nonn,easy
%O 4,1
%A _Artur Jasinski_, Apr 11 2008
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