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%I #5 Jul 14 2012 11:32:20
%S 1,3,6,8,13,17,23,30,40,48,55,65,80,89,98,115,133,144,164,180,198,216,
%T 239,258,282,307,331,357,386,407,431,454,480,505,537,571,604,630,654,
%U 685,717,748,784,820,859,891,925,967,1014,1058,1104,1139,1179,1227,1270
%N Partial sums of A055573 = number of terms in continued fraction of H(n)=sum(1/k,k=1..n).
%C Sequence A100398 holds the array having as n-th row the continued frac. of H(n); a(n) is the last term of the n-th row and accordingly, a(n-1)+1 is the index where the n-th row starts.
%H M. F. Hasler, <a href="/A139001/b139001.txt">Table of n, a(n) for n = 1..500</a>
%F a(n) = sum_{k=1..n} A055573(k)
%o (PARI) h=s=0;vector(100,n,s+=#contfrac(h+=1/n))
%Y Cf. A001008, A002805, A055573, A058027, A100398, A110020, A112286, A112287.
%K nonn
%O 1,2
%A _M. F. Hasler_, May 31 2008
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