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A139001
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Partial sums of A055573 = number of terms in continued fraction of H(n)=sum(1/k,k=1..n).
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3
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1, 3, 6, 8, 13, 17, 23, 30, 40, 48, 55, 65, 80, 89, 98, 115, 133, 144, 164, 180, 198, 216, 239, 258, 282, 307, 331, 357, 386, 407, 431, 454, 480, 505, 537, 571, 604, 630, 654, 685, 717, 748, 784, 820, 859, 891, 925, 967, 1014, 1058, 1104, 1139, 1179, 1227, 1270
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OFFSET
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1,2
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COMMENTS
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Sequence A100398 holds the array having as n-th row the continued frac. of H(n); a(n) is the last term of the n-th row and accordingly, a(n-1)+1 is the index where the n-th row starts.
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LINKS
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FORMULA
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PROG
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(PARI) h=s=0; vector(100, n, s+=#contfrac(h+=1/n))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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