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A138984
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a(n) = Frobenius number for 4 successive numbers = F(n+1,n+2,n+3,n+4).
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6
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1, 2, 3, 9, 11, 13, 23, 26, 29, 43, 47, 51, 69, 74, 79, 101, 107, 113, 139, 146, 153, 183, 191, 199, 233, 242, 251, 289, 299, 309, 351, 362, 373, 419, 431, 443, 493, 506, 519, 573, 587, 601, 659, 674, 689, 751, 767, 783, 849, 866, 883, 953, 971, 989, 1063, 1082
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,2
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COMMENTS
| For Frobenius numbers for 2 successive numbers see A028387
For Frobenius numbers for 3 successive numbers see A079326
For Frobenius numbers for 4 successive numbers see A138984
For Frobenius numbers for 5 successive numbers see A138985
For Frobenius numbers for 6 successive numbers see A138986
For Frobenius numbers for 7 successive numbers see A138987
For Frobenius numbers for 8 successive numbers see A138988
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EXAMPLE
| a(4)=9 because 9 is the biggest number k such that equation:
5*x_1+6*x_2+7*x_3+9*x_4 = k has no solution for any nonnegative x_i
(in other words for every k>9 there exists one or more solutions)
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MATHEMATICA
| Table[FrobeniusNumber[{n + 1, n + 2, n + 3, n + 4}], {n, 1, 100}]
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CROSSREFS
| Cf. A028387, A079326, A138985, A138986, A138987, A138988.
Sequence in context: A103039 A140222 A121557 * A110772 A074338 A111319
Adjacent sequences: A138981 A138982 A138983 * A138985 A138986 A138987
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KEYWORD
| nonn
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AUTHOR
| Artur Jasinski (grafix(AT)csl.pl), Apr 05 2008
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