OFFSET
0,3
COMMENTS
The n-th term of the n-th inverse binomial transform of A138911 is 1 for n>=0.
FORMULA
O.g.f. satisfies: [x^n] A( x/(1+(n-1)*x) )/(1+(n-1)*x) = 1 for n>=0.
E.g.f. satisfies: [x^n] A(x)*exp(-(n-1)*x) = 1/n! for n>=0.
PROG
(PARI) {a(n)=local(A=[1]); for(k=1, n, A=concat(A, 0); A[k+1]=1-polcoeff(subst(Ser(A), x, x/(1+(k-1)*x+x*O(x^k)))/(1+(k-1)*x), k)); A[n+1]}
CROSSREFS
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Apr 05 2008
STATUS
approved