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%I #3 Aug 24 2012 10:50:01
%S 7,17,1711,3117,172113,13311217,17411223,1322311417,1741142322,
%T 3213243117,1731331422,2214313317,1731331422,2214313317,1731331422,
%U 2214313317,1731331422,2214313317,1731331422,2214313317,1731331422
%N Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 7.
%C After a while sequence has period 2 -> {1731331422,2214313317}
%e To get the term after 172113, we say: one 3's, three 1's, one 2's, one 7's, so 13311217
%Y Cf. A063850, A022482, A005150, A005151, A006751, A006715, A006711, A022506-A022513, A138484-A138490, A138492, A138493.
%K easy,nonn,base
%O 0,1
%A _Paolo P. Lava_ and _Giorgio Balzarotti_, Mar 20 2008
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