%I
%S 3,13,1311,3113,2321,112213,133122,222123,134211,31121413,23411412,
%T 22312413,23211432,32231421,21321423,23321421,21321423,23321421,
%U 21321423,23321421,21321423,23321421,21321423,23321421,21321423
%N Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 3.
%C After a while sequence has period 2 > {21321423,23321421}
%e To get the term after 112213, we say: one 3's, three 1's, two 2's, so 133122
%Y Cf. A063850, A022482, A005150, A005151, A006751, A006715, A006711, A022506A022513, A138484A138486, A138488A138493.
%K easy,nonn,base
%O 0,1
%A _Paolo P. Lava_ and _Giorgio Balzarotti_, Mar 20 2008
