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Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 0.
10

%I #3 Aug 24 2012 10:50:01

%S 0,10,1011,3110,102113,13311210,10411223,1322311410,1041142322,

%T 3213243110,1031331422,2214313310,1031331422,2214313310,1031331422,

%U 2214313310,1031331422,2214313310,1031331422,2214313310,1031331422

%N Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 0.

%C After a while sequence has period 2 -> {1031331422,2214313310}

%e To get the term after 102113, we say: one 3's, three 1's, one 2's, one 0's, so 13311210.

%Y Cf. A063850, A022482, A005150, A005151, A006751, A006715, A006711, A022506-A022513, A138485-A138493.

%K easy,nonn,base

%O 0,2

%A _Paolo P. Lava_ and _Giorgio Balzarotti_, Mar 20 2008