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A137937 A137904(n) - A137575(n). 0

%I #8 Apr 18 2013 06:34:16

%S 0,0,3,4,5,6,7,8,9,10,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,

%T 35,36,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,

%U 76,77,78,79,80,81,82,83,84,85,86

%N A137904(n) - A137575(n).

%C To have 0 upon vertical 2, 10, 18, 36, 54, 86 (noble gases) is not a problem (with the help of A137583. A (second) 0 upon 1, 3, 11, 19, 37, 55, 87 (alkali metals), seems paradoxal. Is 120 terms (elements) sequence 0, 0, 1, 2, .. 117, 118 credible? This leads to a row 0 (0 upon hydrogen, 0 upon helium). Two common points with Janet periodic table elements.

%C 60 terms: another, with A137913, theoritical companion to A137904.

%F A137913 prepended with 0, 0.

%Y Cf. A134984, A137575, A137904.

%K nonn,fini,full

%O 0,3

%A _Paul Curtz_, Apr 30 2008

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Last modified April 18 16:22 EDT 2024. Contains 371780 sequences. (Running on oeis4.)