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A137866
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a(1)=0. For n >= 2, a(n) = gcd(a(n-1)+1, n).
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1
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0, 1, 1, 2, 1, 2, 1, 2, 3, 2, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 2, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 2, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 2, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 2, 1, 2, 1, 2, 3, 4, 5, 6, 1, 2, 3, 2, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 2
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OFFSET
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1,4
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COMMENTS
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Starting with a(1) = 1 instead leads to a(n) = n for every positive integer n.
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LINKS
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MATHEMATICA
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a[1] := 0; a[n_] := a[n] = GCD[a[n - 1] + 1, n]; Table[a[n], {n, 82}] (* Alonso del Arte, Feb 14 2011 *)
RecurrenceTable[{a[1]==0, a[n]==GCD[a[n-1]+1, n]}, a, {n, 90}] (* Harvey P. Dale, Aug 02 2016 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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