A137822 - OEIS

%I #11 Jan 26 2021 10:48:05

%S 1,3,2,7,2,3,1,21,2,3,1,8,1,3,2,61,2,3,1,8,1,3,2,21,1,3,2,7,2,3,1,183,

%T 2,3,1,8,1,3,2,21,1,3,2,7,2,3,1,62,1,3,2,7,2,3,1,21,2,3,1,8,1,3,2,547,

%U 2,3,1,8,1,3,2,21,1,3,2,7,2,3,1,62,1,3,2,7,2,3,1,21,2,3,1,8,1,3,2,183,1,3,2

%N First differences of A137821 (numbers such that sum( Catalan(k), k=1..2n) = 0 (mod 3)).

%C For the initial term, we use A137821(0)=0 (cf. formula).

%C Sequence A122983 lists record values of this one, which occur at index 2^j (cf. formula). The fact that these values roughly grow by a factor 3 is explained by the fact that these values are given as the sum of all preceding terms (up to +1 or +2 according to the parity of j, cf. formula).

%C The only values occurring in this sequence are { 1, 2, 3, 7, 8, 21, 61, 62, 183, 547, 548, 1641,... } = A137823, consisting of the record values a(2^j) and, for every other one of these (i.e. for even j), its successor a(2^j)+1, occurring first as a(3*2^j).

%C The remarkably simple sequence A137824 (= 1,3,2, 4,12,8,...: pattern 1,3,2 multiplied by powers of 4) gives the index at which the value A137823(m) first occurs. - M. F. Hasler, Mar 15 2008

%C The PARI code given here (function A137822(n)) allows one to calculate hundreds of terms of A107755 in a few microseconds. - _M. F. Hasler_, Mar 15 2008

%H M. F. Hasler, <a href="/A137822/b137822.txt">Table of n, a(n) for n = 1..499</a>.

%F a(m) = A137821(m)-A137821(m-1), A137821(m)=sum( a(j), j=1..m).

%F a(2^j) = A122983(j-1) = A137821(2^j-1) + 1 (resp. +2) for j even (resp. odd).

%F a(3*2^j) = a(2^j) (resp. = a(2^j)+1) for j odd (resp. j even).

%e Record values are a(1)=1, a(2)=3, a(4)=7, a(8)=21, a(16)=61, ...

%e Apart from these values, the only other values occurring in the sequence are:

%e 2=a(1)+1=a(3*1), 8=a(4)+1=a(3*4), 62=a(16)+1=a(3*16), ...

%o (PARI) A137822 = D( A137821 ) /* where D(v)=vector(#v-1,i,v[i+1]-v[i]) or D(v)=vecextract(v, "^1")-vecextract(v,"^-1") */

%o (PARI) n=0; A137822=vector(499,i,{ o=n; if( bitand(i,i-1), while(n++ && s+=binomial(4*n-2, 2*n-1)/(2*n)*(10*n-1)/(2*n+1),),s=Mod(0,3); n=2*n+1+log(i+.5)\log(2)%2 ); n-o})

%o (PARI) A137822(n)= local( L=log(n+.5)\log(2) ); while( n>0 || ((n+=2^L) && L=log(n+.5)\log(2)), (n-=2^L) || return( 3^(L+1)\4+1 ); (n-=2^(L-1)) || return( 3^L\4+1+L%2 );n<0 && n+=2<<L--);1 \\ _M. F. Hasler_, Mar 15 2008

%Y Cf. A000108, A107755, A137821-A137824.

%Y Cf. A122983 (record values of this).

%K nonn

%O 1,2

%A _M. F. Hasler_, Feb 25 2008, revised Mar 15 2008