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A136799
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Last term in a sequence of at least 3 consecutive composite integers.
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4
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10, 16, 22, 28, 36, 40, 46, 52, 58, 66, 70, 78, 82, 88, 96, 100, 106, 112, 126, 130, 136, 148, 156, 162, 166, 172, 178, 190, 196, 210, 222, 226, 232, 238, 250, 256, 262, 268, 276, 280, 292, 306, 310, 316, 330, 336, 346, 352, 358, 366, 372, 378, 383, 388, 396
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| The BASIC program below is useful in testing Grimm's Conjecture, subject of Carlos Rivera's Puzzle 430
Use the program with lines 30 and 70 enabled in the first run and then disabled with lines 31 and 71 enabled in the second run.
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LINKS
| Carlos Rivera, Puzzle 430, Grimm's Conjecture, Prime puzzles and problems connection.
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FORMULA
| a(n) = A025584(n+2) -1 . - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 24 2008
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EXAMPLE
| a(1)=10 because 10 is the last term in a run of three composites beginning with 8 and ending with 10 (8,9,10).
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PROG
| UBASIC: 10 'puzzle 430 (gap finder) 20 N=1 30 A=1:S=sqrt(N):print N; 31 'A=1:S=N\2:print N; 40 B=N\A 50 if B*A=N and B=prmdiv(B) then print B; 60 A=A+1 70 if A<=sqrt(N) then 40 71 'if A<=N\2 then 40 80 C=C+1:print C 90 N=N+1: if N=prmdiv(N) then C=0:print:stop:goto 90:else 30
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CROSSREFS
| Cf. A136798, A136800, A136801.
Sequence in context: A129848 A083118 A004261 * A055987 A187397 A152138
Adjacent sequences: A136796 A136797 A136798 * A136800 A136801 A136802
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KEYWORD
| easy,nonn
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AUTHOR
| Enoch Haga (Enokh(AT)comcast.net), Jan 21 2008
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EXTENSIONS
| Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), May 27 2009
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