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A136465 Row 0 of square array A136462: a(n) = C(2^(n-1), n) for n>=0. 5
1, 1, 1, 4, 70, 4368, 906192, 621216192, 1429702652400, 11288510714272000, 312268282598377321216, 30813235422145714150738944, 11005261717918037175659349191168 (list; graph; refs; listen; history; internal format)
OFFSET

0,4

COMMENTS

a(n) is found in row n, column 0, of triangle A136467 for n>=0.

For n > 0, number of increasing integer sequences 1 <= a_1 < ... < a_n <= 2^(n-1). [From Charles R Greathouse IV (charles.greathouse(AT)case.edu), Aug 08 2010]

FORMULA

a(n) = [x^n] Sum_{i>=0} (1/2)^i * log(1 + 2^i*x)^i/i!.

G.f.: A(x) = Sum_{n>=0} log(1 + 2^n*x)^n/(n!*2^n) ). [From Paul D. Hanna (pauldhanna(AT)juno.com), Sep 26 2010]

EXAMPLE

Contribution from Paul D. Hanna (pauldhanna(AT)juno.com), Sep 26 2010: (Start)

G.f.: A(x) = 1 + x + x^2 + 4*x^3 + 70*x^4 + 4368*x^5 +...

A(x) = 1 + log(1+2*x)/2 + log(1 + 2^2*x)^2/(2!*2^2) + log(1 + 2^3*x)^3/(3!*2^3) + log(1 + 2^4*x)^4/(4!*2^4) +... (End)

PROG

(PARI) {a(n)=binomial(2^(n-1), n)} (PARI) /* a(n) = Coefficient of x^k in series: */ {a(n)=polcoeff(sum(i=0, n, (1/2)^i*log(1+2^i*x +x*O(x^n))^i/i!), n)}

(PARI) {a(n)=polcoeff(sum(m=0, n, log(1+2^m*x+x*O(x^n))^m/(m!*2^m)), n)} [From Paul D. Hanna (pauldhanna(AT)juno.com), Sep 26 2010]

CROSSREFS

Cf. A136462; other rows: A014070, A136466, A101346; A136467.

Sequence in context: A065573 A101841 A061609 * A184576 A162135 A047939

Adjacent sequences:  A136462 A136463 A136464 * A136466 A136467 A136468

KEYWORD

nonn

AUTHOR

Paul D. Hanna (pauldhanna(AT)juno.com), Dec 31 2007

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Last modified February 17 19:13 EST 2012. Contains 206085 sequences.