OFFSET
0,2
COMMENTS
a(n) is divisible by (n+1) for n>=0: a(n)/(n+1) = A136464(n).
FORMULA
a(n) = [x^n] Sum_{i>=0} ((n+1)/2)^i * log(1 + 2^i*x)^i/i!.
a(n) is found in row n, column 0, of matrix power A136467^(n+1) for n>=0.
a(n) ~ exp(n+1) * 2^(n*(n-1)) / sqrt(2*Pi*n). - Vaclav Kotesovec, Jul 02 2016
MATHEMATICA
Table[Binomial[(n+1)2^(n-1), n], {n, 0, 15}] (* Harvey P. Dale, Apr 20 2011 *)
PROG
(PARI) a(n)=binomial((n+1)*2^(n-1), n)
(PARI) /* a(n) = Coefficient of x^n in series: */
a(n)=polcoeff(sum(i=0, n, ((n+1)/2)^i*log(1+2^i*x +x*O(x^n))^i/i!), n)
CROSSREFS
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Dec 31 2007
STATUS
approved