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a(n) = A136380(n)/4.
6

%I #4 Mar 31 2012 14:02:29

%S 6,40,2992,12414272,209257095067008,59317480525187181808940067328,

%T 4702813293407424109748719392353175027867348964750888938496,

%U 29544706650695305166306664670066298727078147700457878444083332544832412373927109119211594757559616821553159371673600

%N a(n) = A136380(n)/4.

%C Note that each term a(n) fits into A007283(n-1) bits.

%H A. Karttunen, <a href="/A136382/b136382.txt">Table of n, a(n) for n = 1..11</a>

%H A. Karttunen, <a href="/A036284/a036284.c.txt">C program for computing this sequence</a>

%Y a(n) = A048724(A136384(n))/2. A136383 shows the same sequence in octal base. Cf. A036284.

%K nonn,base

%O 1,1

%A _Antti Karttunen_, Dec 29 2007