|
|
A136347
|
|
a(1)=1. Let m be the number of terms in the longest run of consecutive equal terms from among the first n terms of the sequence. a(n+1) = the number of terms, from among the first n terms of the sequence, that are coprime to m.
|
|
2
|
|
|
1, 1, 2, 2, 2, 5, 6, 6, 6, 6, 3, 4, 4, 4, 4, 4, 15, 15, 15, 15, 15, 15, 3, 3, 3, 3, 3, 3, 3, 29, 30, 31, 32, 33, 34, 35, 35, 35, 35, 35, 35, 35, 35, 28, 28, 28, 28, 28, 28, 28, 28, 28, 32, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 23, 24, 24, 24, 24, 24, 24, 24
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,3
|
|
LINKS
|
|
|
EXAMPLE
|
Among the first 30 terms of the sequence the run of seven 3's (from a(23) to a(29)) is the longest run of consecutive equal terms. (So m = 7.) Among the first 30 terms of the sequence, all 30 terms are coprime to 7. So a(31) = 30.
|
|
PROG
|
(PARI) See Links section.
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|