%I #7 Mar 11 2014 01:32:23
%S 1,1,1,2,1,2,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,4,5,1,2,3,4,1,2,3,1,
%T 2,3,4,5,1,2,3,4,1,2,3,1,2,3,4,5,1,2,3,4,1,2,3,1,2,3,4,5,1,2,3,4,1,2,
%U 3,1,2,3,4,5,1,2,3,4,1,2,3,1,2,3,4,5,1,2,3,4,5,6,7,1,2,3,4,5,6,7,8,9,1,2,3
%N a(0) = a(1) = 1. The n-th run (after the initial two 1's) of (a(n)+a(n-1)) terms is (1,2,3,...,a(n)+a(n-1)).
%e Runs (after the initial first two 1's) each placed in parentheses:
%e (Notice that n-th run in parentheses contains exactly a(n)+a(n-1) terms.)
%e 1, 1, (1, 2), (1, 2), (1, 2, 3), (1, 2, 3), (1, 2, 3), (1, 2, 3), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4, 5, 6, 7), (1, 2, 3, 4, 5, 6, 7, 8, 9), (1, 2, 3, 4, 5, 6), (1, 2, 3), (1, 2, 3, 4, 5), (1, 2, 3, 4, 5, 6, 7)
%K easy,nonn
%O 0,4
%A _Leroy Quet_, Mar 23 2008