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A136136
a(n+1)=sopfr(2a(n)+1), with sopfr=A001414. Finishes with 10 (fixed point).
5
1, 3, 7, 8, 17, 12, 10
OFFSET
1,2
COMMENTS
The class of recurrence sequences a(n+1)=sopfr(C*a(n)+D) may finish with a fixed point or with a cycle.
FORMULA
a(n+1)=A001414(2*a(n)+1)
MATHEMATICA
sopfr = Function[x, Plus @@ Map[Times @@ # &, FactorInteger[x]]]; NestList[sopfr[2# + 1] &, 1, 10]
CROSSREFS
Cf. A001414.
Sequence in context: A263519 A105263 A242572 * A057548 A122227 A259571
KEYWORD
fini,full,nonn
AUTHOR
Carlos Alves, Dec 16 2007
STATUS
approved