A136136 a(n+1)=sopfr(2a(n)+1), with sopfr=A001414. Finishes with 10 (fixed point).

1, 3, 7, 8, 17, 12, 10

Offset

1,2

Comments

The class of recurrence sequences a(n+1)=sopfr(C*a(n)+D) may finish with a fixed point or with a cycle.

Links

Table of n, a(n) for n=1..7.

Formula

a(n+1)=A001414(2*a(n)+1)

Mathematica

sopfr = Function[x, Plus @@ Map[Times @@ # &, FactorInteger[x]]]; NestList[sopfr[2# + 1] &, 1, 10]

Crossrefs

Cf. A001414.

Sequence in context: A263519 A105263 A242572 * A057548 A122227 A259571

Adjacent sequences: A136133 A136134 A136135 * A136137 A136138 A136139

Keyword

fini,full,nonn

Author

Carlos Alves, Dec 16 2007

Status

approved