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A135503 a(n) = n*(n^2 - 1)/2. 9

%I #69 Jun 03 2023 10:16:53

%S 0,0,3,12,30,60,105,168,252,360,495,660,858,1092,1365,1680,2040,2448,

%T 2907,3420,3990,4620,5313,6072,6900,7800,8775,9828,10962,12180,13485,

%U 14880,16368,17952,19635,21420,23310,25308,27417,29640,31980,34440

%N a(n) = n*(n^2 - 1)/2.

%C Previous name was: Integer values of sqrt(b) solving sqrt(d) + sqrt(b) = sqrt(c) with d^2 + b = c.

%C Squaring the first equation and setting the result equal to the second, we need d + b + 2*sqrt(d*b) = d^2+b -> d + 2*sqrt(d*b) = d^2 -> d^2 - d = 2*sqrt(d*b)

%C -> d^2*(d-1)^2 = 4*d*b -> b = d*(d-1)^2/4 -> sqrt(b) = (d-1)*sqrt(d)/2. Setting d = (n+1)^2 yields sqrt(b) = A027480(n).

%C This is the case k = 2 for FLTR, Fermat's Last Theorem with rational exponents 1/k: Consider x + y = x + y. Then (x^k)^(1/k) + (y^k)^(1/k) = ((x+y)^k)^(1/k).

%C For k > 2, there are infinitely many solutions to d^(1/k) + b^(1/k) = c^(1/k). E.g., 8^(1/3) + 27^(1/3) = 125^(1/3) at k = 3. However, in conjunction with d^2 + b = c, I could not find any nontrivial solutions.

%C A shifted version of A027480. - _R. J. Mathar_, Apr 07 2009

%C For n > 2, a(n) is the maximum value of the magic constant in a perimeter-magic n-gon of order n (see A342758). - _Stefano Spezia_, Mar 21 2021

%C a(n) is equal to the total number of P_3 edge-disjoint subgraphs of the complete graph on n vertices. - _Samuel J. Bevins_, May 09 2023

%H G. C. Greubel, <a href="/A135503/b135503.txt">Table of n, a(n) for n = 0..1000</a>

%H C. D. Bennet, A. M. W. Glass and G. J. Székely, <a href="http://www.jstor.org/stable/4145241">Fermat's Last Theorem for Rational Exponents</a>, Am. Math. Monthly 111 (2004), 322-329. - _R. J. Mathar_, Apr 21 2009

%H Terrel Trotter, <a href="https://web.archive.org/web/20070106085340/http://www.trottermath.net/simpleops/pmp.html">Perimeter-Magic Polygons</a>, Journal of Recreational Mathematics Vol. 7, No. 1, 1974, pp. 14-20.

%F From _R. J. Mathar_ Feb 20 2008: (Start)

%F O.g.f.: 3*x^2/(-1+x)^4.

%F a(n) = n*(n^2 - 1)/2 = A007531(n+1)/2. (End)

%F G.f.: 3*x^2*G(0)/2, where G(k) = 1 + 1/(1 - x/(x + (k+1)/(k+4)/G(k+1))); (continued fraction). - _Sergei N. Gladkovskii_, Jun 01 2013

%F a(n) = A006003(n+1) - A000326(n+1). - _J. M. Bergot_, Dec 04 2014

%F E.g.f.: (1/2)* x^2 *(3 + x)*exp(x). - _G. C. Greubel_, Oct 15 2016

%F From _Miquel Cerda_, Dec 25 2016: (Start)

%F a(n) = A000578(n) - A006003(n).

%F a(n) = A004188(n) - A000578(n).

%F a(n) = A007588(n) - A004188(n). (End)

%F a(n) = A002411(n) - A000217(n). - _Justin Gaetano_, Feb 20 2018

%F From _Amiram Eldar_, Jan 09 2021: (Start)

%F Sum_{n>=2} 1/a(n) = 1/2.

%F Sum_{n>=2} (-1)^n/a(n) = 4*log(2) - 5/2. (End)

%e For d = 9, b = 144, c = 225, 9^(1/2) + 144^(1/2) = 225^(1/2) and 9^2 + 144 = 225. So b^(1/2) = 12 is the 4th entry in the sequence.

%t Array[# (#^2 - 1)/2 &, 42, 0] (* _Michael De Vlieger_, Feb 20 2018 *)

%o (PARI) flt2(n,p) = { local(a,b); for(a=0,n, b = (a^3-a)/2; print1(b", ") ) }

%Y Cf. A000217, A000578, A002411, A004188, A006003, A007531, A007588, A027480, A342758.

%K nonn,easy

%O 0,3

%A _Cino Hilliard_, Feb 09 2008

%E Edited by _R. J. Mathar_, Apr 21 2009

%E New name using _R. J. Mathar_'s formula, _Joerg Arndt_, Dec 05 2014

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Last modified April 19 16:52 EDT 2024. Contains 371794 sequences. (Running on oeis4.)