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A134972 Decimal expansion of 2 divided by golden ratio = 2/phi = 4/(1 + sqrt(5)) = 2*(-1 + phi). 10

%I

%S 1,2,3,6,0,6,7,9,7,7,4,9,9,7,8,9,6,9,6,4,0,9,1,7,3,6,6,8,7,3,1,2,7,6,

%T 2,3,5,4,4,0,6,1,8,3,5,9,6,1,1,5,2,5,7,2,4,2,7,0,8,9,7,2,4,5,4,1,0,5,

%U 2,0,9,2,5,6,3,7,8,0,4,8,9,9,4,1,4,4,1,4,4,0,8,3,7,8,7,8,2,2,7,4,9,6,9,5

%N Decimal expansion of 2 divided by golden ratio = 2/phi = 4/(1 + sqrt(5)) = 2*(-1 + phi).

%C Convergents are 4/2, 8/8, 32/24, 96/80, 320/256, 1024/832, 3328/2688, 10752/8704, 34816/28160, 112640/91136, 364544/294912, 1179648/954368, 3817472/3088384, 12353536/9994240,... = A209084/A063727. - _Seiichi Kirikami_, Mar 14 2012

%C 2*(-1 + phi)) is an integer in the quadratic number field Q(sqrt(5)). - _Wolfdieter Lang_, Feb 16 2016

%F Equals A134945 - 2 = A002163 - 1 = A098317 - 3. [_R. J. Mathar_, Oct 27 2008]

%F 2*(-1 + A001622). - _Wolfdieter Lang_, Feb 17 2016

%F Equals the harmonic mean of 1 and phi, 2*phi/(1+phi). - _Stanislav Sykora_, Apr 11 2016

%F From _Christian Katzmann_, Mar 19 2018: (Start)

%F Equals Sum_{n>=0} (15*(2*n)!-8*n!^2)/(n!^2*3^(2*n+2)).

%F Equals -1 + Sum_{n>=0} 5*(2*n)!/(n!^2*3^(2*n+1)). (End)

%F Equals 1/A019863. - _R. J. Mathar_, Jan 17 2021

%e 1.236067977499789696...

%t RealDigits[ N[4/(1+Sqrt[5]), 150] ] [ [1] ] (* _Seiichi Kirikami_, Mar 14 2012 *)

%o (PARI) 4/(1+sqrt(5)) \\ _Altug Alkan_, Apr 11 2016

%Y Cf. A001622, A019863, A063727, A209084, A033887.

%K cons,nonn

%O 1,2

%A _Omar E. Pol_, Nov 15 2007

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Last modified February 24 12:52 EST 2021. Contains 341569 sequences. (Running on oeis4.)