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 A134972 Decimal expansion of 2 divided by golden ratio = 2/phi = 4/(1 + sqrt(5)) = 2*(-1 + phi). 9
 1, 2, 3, 6, 0, 6, 7, 9, 7, 7, 4, 9, 9, 7, 8, 9, 6, 9, 6, 4, 0, 9, 1, 7, 3, 6, 6, 8, 7, 3, 1, 2, 7, 6, 2, 3, 5, 4, 4, 0, 6, 1, 8, 3, 5, 9, 6, 1, 1, 5, 2, 5, 7, 2, 4, 2, 7, 0, 8, 9, 7, 2, 4, 5, 4, 1, 0, 5, 2, 0, 9, 2, 5, 6, 3, 7, 8, 0, 4, 8, 9, 9, 4, 1, 4, 4, 1, 4, 4, 0, 8, 3, 7, 8, 7, 8, 2, 2, 7, 4, 9, 6, 9, 5 (list; constant; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Convergents are 4/2, 8/8, 32/24, 96/80, 320/256, 1024/832, 3328/2688, 10752/8704, 34816/28160, 112640/91136, 364544/294912, 1179648/954368, 3817472/3088384, 12353536/9994240,... = A209084/A063727. - Seiichi Kirikami, Mar 14 2012 2*(-1 + phi)) is an integer in the quadratic number field Q(sqrt(5)). - Wolfdieter Lang, Feb 16 2016 LINKS FORMULA Equals A134945 - 2 = A002163 - 1 = A098317 - 3. [R. J. Mathar, Oct 27 2008] 2*(-1 + A001622). - Wolfdieter Lang, Feb 17 2016 Equals the harmonic mean of 1 and phi, 2*phi/(1+phi). - Stanislav Sykora, Apr 11 2016 From Christian Katzmann, Mar 19 2018: (Start) Equals Sum_{n>=0} (15*(2*n)!-8*n!^2)/(n!^2*3^(2*n+2)). Equals -1 + Sum_{n>=0} 5*(2*n)!/(n!^2*3^(2*n+1)). (End) Equals 1/A019863. - R. J. Mathar, Jan 17 2021 EXAMPLE 1.236067977499789696... MATHEMATICA RealDigits[ N[4/(1+Sqrt[5]), 150] ] [ [1] ] (* Seiichi Kirikami, Mar 14 2012 *) PROG (PARI) 4/(1+sqrt(5)) \\ Altug Alkan, Apr 11 2016 CROSSREFS Cf. A001622, A019863, A063727, A209084, A033887. Sequence in context: A331205 A075174 A075176 * A078890 A021813 A082052 Adjacent sequences:  A134969 A134970 A134971 * A134973 A134974 A134975 KEYWORD cons,nonn,changed AUTHOR Omar E. Pol, Nov 15 2007 STATUS approved

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Last modified January 21 12:45 EST 2021. Contains 340350 sequences. (Running on oeis4.)