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%I #16 Nov 30 2015 09:35:29
%S 1,1,1,1,1,2,3,2,1,2,5,9,11,7,3,3,10,26,40,40,21,6,5,25,77,159,217,
%T 185,85,19,9,56,222,575,1031,1230,920,356,50,18,139,654,2082,4679,
%U 7437,7982,5308,1804,204,35,338,1902,7244,19983,40139,57771,56437,33860,10064,832
%N Irregular triangle read by rows: the number of hydrocarbon structures that can be drawn with a given number of carbons and units of unsaturation.
%C Computed over a period of several years and confirmed using the Molgen program.
%H David Consiglio, Jr., <a href="/A134819/b134819.txt">Table of n, a(n) for n = 1..130</a>
%H Molgen, <a href="http://molgen.de/?src=documents/publications">Molecular Structure Generation</a>
%e Triangle begins:
%e 1
%e 1 1 1
%e 1 2 3 2 1
%e 2 5 9 11 7 3
%e etc.
%e a(3,1) = 2 because there are two structures that contain 3 carbons and have 1 unit of unsaturation (propene and cyclopropane).
%Y Row sums give A134818.
%K nice,nonn,tabf
%O 1,6
%A _David Consiglio, Jr._, Jan 28 2008, Apr 23 2008
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