|
%I #11 Apr 05 2020 21:24:30
%S 0,0,1,2,1,1,3,2,2,2,4,2,2,3,2,2,2,5,4,4,3,2,3,3,4,3,3,3,6,3,3,4,3,3,
%T 3,5,4,4,3,2,3,3,4,3,3,3,7,6,6,5,4,5,5,5,4,4,3,2,4,4,5,4,4,4,6,5,5,4,
%U 3,4,4,5,4,4,4,8,4,4,5,4,4,4,6,5,5,4,3,4,4,5,4,4,4,7,6,6,5,4,5,5,5,4,4,3,2
%N Number of 0's in the maximal "phinary" (A130601) representation of n.
%D Zeckendorf, E., Représentation des nombres naturels par une somme des nombres de Fibonacci ou de nombres de Lucas, Bull. Soc. Roy. Sci. Liège 41, 179-182, 1972.
%H Casey Mongoven, <a href="/A133776/b133776.txt">Table of n, a(n) for n = 1..199</a>
%H Ron Knott, <a href="http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/phigits.html">Using Powers of Phi to represent Integers</a>.
%e A130601(7)=10101101, which has three 0's. So a(7)=3.
%Y Cf. A133775, A130601.
%K nonn
%O 1,4
%A _Casey Mongoven_, Sep 23 2007
|
