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a(n) = round( 2*Gamma(3 + n/3) + 2^(n/3) ).
1

%I #6 Apr 13 2021 03:43:23

%S 5,7,10,14,21,33,52,85,144,248,438,791,1456,2731,5213,10112,19920,

%T 39819,80704,165749,344758,725888,1546398,3331879,7257856,15978098,

%U 35538283,79834112,181082105,414609369,958004224,2233339296,5251710002,12454043648,29777842663,71773351064,174356586496,426815713006,1052675774422

%N a(n) = round( 2*Gamma(3 + n/3) + 2^(n/3) ).

%H G. C. Greubel, <a href="/A133756/b133756.txt">Table of n, a(n) for n = 0..1000</a>

%F a(n) = round(2*Gamma(f(n) + 3) + 2^f(n)), where f(n) = n/3.

%t Table[Round[2*Gamma[3+n/3] + 2^(n/3)], {n, 0, 40}] (* modified by _G. C. Greubel_, Apr 13 2021 *)

%o (Magma) [Round(2*Gamma(n/3 + 3) + 2^(n/3)): n in [0..40]]; // _G. C. Greubel_, Apr 13 2021

%o (Sage) [round(2*gamma(n/3 + 3) + 2^(n/3)) for n in (0..40)] # _G. C. Greubel_, Apr 13 2021

%K nonn

%O 0,1

%A _Roger L. Bagula_, Jan 01 2008

%E Edited by _G. C. Greubel_, Apr 13 2021