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%I #8 Nov 21 2013 12:49:07
%S 3400,20175,180983,549151,1952201,4267249,10332299,29423591,55576643,
%T 118484257,213829309,332208601,492209651,794548943,1362464799,
%U 1977716093,2909645707,3998950759,5227426051,6954357343,9089168635
%N Sum of fifth powers of three consecutive primes.
%F a(n) = A133536(n) + A050997(n+2). - _Michel Marcus_, Nov 09 2013
%e a(1)=3400 because 2^5+3^5+5^5=3400.
%t a = 5; Table[Prime[n]^a + Prime[n + 1]^a + Prime[n + 2]^a, {n, 1, 100}]
%t Total[#^5]&/@Partition[Prime[Range[30]],3,1] (* _Harvey P. Dale_, May 26 2011 *)
%Y Cf. A034963, A133524, A133525, A133526, A133527, A133528, A133529, A133530, A133531, A133533.
%K nonn
%O 1,1
%A _Artur Jasinski_, Sep 14 2007
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