%I #5 Nov 08 2013 12:13:43
%S 160,495,1799,3871,8441,13969,23939,43415,66347,104833,149365,199081,
%T 252251,332207,458079,581237,733123,885655,1047691,1239967,1453843,
%U 1769795,2189429,2647943,3035701,3348071,3612799,3962969,4786309
%N Sum of third powers of three consecutive primes.
%F a(n) = A133534(n) + A030078(n+2). - _Michel Marcus_, Nov 08 2013
%e a(1)=160 because 2^3+3^3+5^3=160.
%t a = 3; Table[Prime[n]^a + Prime[n + 1]^a + Prime[n + 2]^a, {n, 1, 100}]
%Y Cf. A034963, A133524, A133525, A133526, A133527, A133528, A133529, A133531, A133532, A133533.
%K nonn
%O 1,1
%A _Artur Jasinski_, Sep 14 2007
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