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A133393
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Start with a(1)=1; for n >= 1, a(n+1)=a(n)+a(k) with k=[n - n-th digit of sqrt(2)]. If k<0 or k=0, then a(k)=0.
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1
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1, 1, 1, 2, 2, 3, 5, 7, 8, 9, 16, 23, 25, 34, 68, 71, 87, 174, 208, 224, 247, 494, 741, 828, 899, 986, 1194, 2093, 2921, 4115, 8230, 8724, 9710, 10538, 11524, 23048, 25969, 28890, 38600, 48310, 56540, 68064, 79588, 147652, 170700, 199590, 256130, 403782
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OFFSET
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1,4
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COMMENTS
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Terms computed by Gilles Sadowski.
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LINKS
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EXAMPLE
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For n=7 we have a(8)=a(7)+a(k) with k=(7-3) because "3" is the 7th digit of sqrt(2): 1,4,1,4,2,1,(3),5,6,2,3,... So a(8)=a(7)+a(4)=5+2=7.
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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STATUS
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approved
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