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A133180
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sum[k^6]/sum[k^2], {k, 1, A047380(n)}].
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6
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1, 13, 163, 373, 2191, 3433, 7411, 10363, 24583, 31591, 49981, 61723, 109513, 130351, 180793, 210901, 324013, 370273, 477463, 539041, 759811, 846613, 1042303, 1151983, 1533331, 1679323, 2002321, 2180263, 2785693, 3013051, 3509221
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OFFSET
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0,2
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COMMENTS
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LINKS
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FORMULA
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a(n) = sum[k^6]/sum[k^2], {k, 1, A047380(n)}]
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MATHEMATICA
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a = {}; Do[j = Sum[k^6, {k, 1, n}]/Sum[k^2, {k, 1, n}]; If[IntegerQ[j], AppendTo[a, j]], {n, 1, 100}] ; a (*Artur Jasinski*)
Select[Table[Sum[k^6, {k, n}]/Sum[k^2, {k, n}], {n, 100}], IntegerQ] (* Harvey P. Dale, Nov 26 2019 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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