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%I #11 Mar 06 2022 00:16:47
%S 1,0,2,0,2,3,0,0,9,4,0,0,6,24,5,0,0,0,40,50,6,0,0,0,20,150,90,7,0,0,0,
%T 0,175,420,147,8,0,0,0,0,70,840,980,224,9,0,0,0,0,0,756,2940,2016,324,
%U 10,0,0,0,0,0,252,4410,8400,3780,450,11
%N A007318^(-1) * A132813.
%C Row sums = A005773 starting (1, 2, 5, 13, 35, 96, ...).
%F Inverse binomial transform of A132813.
%e First few rows of the triangle:
%e 1;
%e 0, 2;
%e 0, 2, 3;
%e 0, 0, 9, 4;
%e 0, 0, 6, 24, 5;
%e 0, 0, 0, 40, 50, 6;
%e 0, 0, 0, 20, 150, 90, 7;
%e ...
%o (PARI) tabl(nn) = {t007318 = matrix(nn, nn, n, k, binomial(n-1, k-1)); t132813 = matrix(nn, nn, n, k, binomial(n-1, k-1)*binomial(n, k-1)); t132814 = t007318^(-1)*t132813; for (n=1, nn, for (k=1, n, print1(t132814[n, k], ", ");););} \\ _Michel Marcus_, Feb 12 2014
%Y Cf. A132813, A005773.
%K nonn,tabl
%O 0,3
%A _Gary W. Adamson_, Sep 01 2007
%E More terms from _Michel Marcus_, Feb 12 2014
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