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A132633
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Minimal m > 0 such that Fibonacci(m) == 0 (mod n^3).
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4
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1, 6, 36, 48, 125, 36, 392, 384, 972, 750, 1210, 144, 1183, 1176, 4500, 3072, 2601, 972, 6498, 6000, 3528, 3630, 12696, 1152, 15625, 7098, 26244, 2352, 11774, 4500, 28830, 24576, 21780, 5202, 49000, 3888, 26011, 6498, 42588, 48000, 33620, 3528, 81356
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OFFSET
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1,2
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COMMENTS
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a(n) is a divisor of the Pisano period A001175(n^3).
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LINKS
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FORMULA
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EXAMPLE
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a(6)=36, since Fib(36)=14930352==0(mod 6^3), but Fib(k) is not congruent to 0 modulo (6^3) for 1<=k<36.
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MATHEMATICA
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Join[{1}, Table[a = {0, 1}; k = 0; While[k++; s = Mod[Plus @@ a, n^3]; a = RotateLeft[a]; a[[2]] = s; a[[1]] != 0]; k, {n, 2, 50}]] (* T. D. Noe, Aug 08 2012 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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