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A132632
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Minimal m > 0 such that Fibonacci(m) == 0 (mod n^2).
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5
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1, 6, 12, 12, 25, 12, 56, 48, 108, 150, 110, 12, 91, 168, 300, 192, 153, 108, 342, 300, 168, 330, 552, 48, 625, 546, 972, 168, 406, 300, 930, 768, 660, 306, 1400, 108, 703, 342, 1092, 1200, 820, 168, 1892, 660, 2700, 552, 752, 192, 2744, 3750, 612, 1092
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OFFSET
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1,2
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COMMENTS
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a(n) is a divisor of the Pisano period A001175(n^2).
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LINKS
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FORMULA
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EXAMPLE
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a(4)=12, since Fib(12)=144==0(mod 4^2), but Fib(k) is not congruent to 0 modulo (4^2) for 1<=k<12.
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MATHEMATICA
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Join[{1}, Table[a = {0, 1}; k = 0; While[k++; s = Mod[Plus @@ a, n^2]; a = RotateLeft[a]; a[[2]] = s; a[[1]] != 0]; k, {n, 2, 60}]] (* T. D. Noe, Aug 08 2012 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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