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A132597
Let S be the concatenation of natural numbers in ternary representation: a(n) = position of first occurrence of n in S, then this occurrence in S is replaced by a(n) in ternary.
6
1, 2, 3, 5, 1, 8, 5, 6, 14, 2, 18, 21, 24, 12, 3, 1, 6, 14, 6, 40, 16, 29, 15, 5, 3, 30, 62, 27, 70, 1, 5, 3, 25, 37, 86, 19, 36, 98, 71, 30, 111, 5, 11, 121, 126, 114, 136, 1, 28, 2, 1, 60, 30, 156, 120, 166, 7, 123, 106, 58, 5, 6, 38, 23, 57, 36, 83, 147, 4, 38, 27, 226, 31, 177
OFFSET
1,2
COMMENTS
A132598(n) = smallest m such that a(m) = n.
A132599 and A132600 give record values and where they occur.
From Michel Marcus, Nov 12 2023: (Start)
Numbers m such that a(m) = m: 1, 2, 3, 4515, ...
Positions m such that a(m)=a(m-1): 386, 829, ... (End)
LINKS
EXAMPLE
S(0) = 12101112202122100101102110111112..;
for n<=3: a(n)=n, S(n) = S(n-1);
n=4->'11', a(4)=5->'12', S(4)=12101212202122100101102110111112..;
n=5->'12', a(5)=1->'1', S(5)=1101212202122100101102110111112..;
n=6->'20', a(6)=8->'22', S(6)=1101212222122100101102110111112..;
n=7->'21', a(7)=5->'12', S(7)=1101122222122100101102110111112..;
n=8->'22', a(8)=6->'20', S(8)=1101120222122100101102110111112..;
n=9->'100', a(9)=14->'112', S(9)=1101120222122112101102110111112..;
n=10->'101', a(10)=2->'2', S(10)=12120222122112101102110111112..;
n=11->'102', a(11)=18->'200', S(11)=12120222122112101200110111112..;
n=12->'110', a(12)=21->'210', S(12)=12120222122112101200210111112..;
n=13->'111', a(13)=24->'220', S(13)=12120222122112101200210220112..;
n=14->'112', a(14)=12->'110', S(14)=12120222122110101200210220112..;
n=15->'120', a(15)=3->'10', S(15)=1210222122110101200210220112..;
n=16->'121', a(16)=1->'1', S(16)=10222122110101200210220112..;
n=17->'122', a(17)=6->'20', S(17)=1022220110101200210220112..;
n=18->'200', a(18)=14->'112', S(18)=1022220110101112210220112..;
n=19->'201', a(19)=6->'20', S(19)=102222010101112210220112.. .
CROSSREFS
KEYWORD
nonn,base,look
AUTHOR
Reinhard Zumkeller, Aug 24 2007
STATUS
approved