1,2
a(n) = reverse(4*a(n-1)) where a(1) = 1
a(4) = reverse(4*a(3)) = reverse(4*reverse(4*a(2))) = reverse(4*reverse(4*reverse(4*a(1)))) = reverse(4*reverse(4*4)) = reverse(4*61) = reverse(244) = 442
Cf. A133361, A045539.
Sequence in context: A129452 A131014 A118005 * A102193 A166028 A054958
Adjacent sequences: A132061 A132062 A132063 * A132065 A132066 A132067
base,nonn
Rachit Agrawal (rachit_agrawal(AT)daiict.ac.in), Oct 30 2007
