login
This site is supported by donations to The OEIS Foundation.

 

Logo


Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A131773 Epact in Julian calendar for a year n with Golden Number (n mod 19) + 1 = A074805(n). 0
30, 11, 22, 3, 14, 25, 6, 17, 28, 9, 20, 1, 12, 23, 4, 15, 26, 7, 18, 30, 11, 22, 3, 14, 25, 6, 17, 28, 9, 20, 1, 12, 23, 4, 15, 26, 7, 18, 30, 11, 22, 3, 14, 25, 6, 17, 28, 9, 20, 1, 12, 23, 4, 15, 26, 7, 18, 30, 11, 22, 3, 14, 25, 6, 17, 28, 9, 20, 1, 12, 23, 4, 15, 26, 7, 18, 30, 11 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,1

COMMENTS

Periodic with period 19 as there are 19 Golden Numbers. Basis for calculating Gregorian Epact. See sections about Epacts, Golden Numbers and discussion of the 19-year Metonic cycle (in Chapter 1) of the Calendar FAQ link. The FAQ also discusses in detail in which years the different calendars have been adopted by different countries and that there was no year 0 (unless considering, say, a "proleptic" Gregorian calendar) -- so the first term here (and in A074805) is actually for 1 BC (1 BCE) of the Julian calendar.

LINKS

Table of n, a(n) for n=0..77.

Claus Tondering, Frequently Asked Questions about Calendars.

Index entries for linear recurrences with constant coefficients, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

FORMULA

a(n) = (11*(A074805(n)-1)) mod 30, but replacing every 0 result with 30. See program and link.

G.f.: (18*x^18 +7*x^17 +26*x^16 +15*x^15 +4*x^14 +23*x^13 +12*x^12 +x^11 +20*x^10 +9*x^9 +28*x^8 +17*x^7 +6*x^6 +25*x^5 +14*x^4 +3*x^3 +22*x^2 +11*x +30)/(-x^19 +1). - Colin Barker, Jul 18 2013

EXAMPLE

a(2007)=12 as the Julian Epact for the year 2007 is (11*(2007 mod 19)) mod 30 = (11*12) mod 30 = 12. ((2007 mod 19)+1 = 12+1 = 13 = A074805(2007) is the corresponding Golden Number for 2007).

MATHEMATICA

LinearRecurrence[{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1}, {30, 11, 22, 3, 14, 25, 6, 17, 28, 9, 20, 1, 12, 23, 4, 15, 26, 7, 18}, 78] (* Ray Chandler, Aug 27 2015 *)

PROG

(PARI) a(n)= JE=(11*(n%19))%30; if(JE==0, 30, JE)

CROSSREFS

Cf. A074805.

Sequence in context: A287921 A073401 A040875 * A091746 A040874 A147454

Adjacent sequences:  A131770 A131771 A131772 * A131774 A131775 A131776

KEYWORD

nonn,easy

AUTHOR

Rick L. Shepherd, Jul 14 2007

STATUS

approved

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recent | More pages
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy .

Last modified February 24 11:39 EST 2018. Contains 299603 sequences. (Running on oeis4.)