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A131639 Numbers n such that the sum of all numbers formed by deleting one digit from n is equal to n. 1
1729404, 1800000, 13758846, 13800000, 14358846, 14400000, 15000000, 28758846, 28800000, 29358846, 29400000, 1107488889, 1107489042, 1111088889, 1111089042, 3277800000, 3281400000, 4388888889, 4388889042, 4392488889, 4392489042, 4500000000, 5607488889, 5607489042, 5611088889, 5611089042, 7777800000, 7781400000, 8888888889, 8888889042, 8892488889, 8892489042, 10000000000, 20000000000, 30000000000, 40000000000, 50000000000, 60000000000, 70000000000, 80000000000, 90000000000 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

LINKS

Table of n, a(n) for n=1..41.

FORMULA

For a number with n digits there are n substrings generated by removing one digit from the original number. So for 12345, these are 2345, 1345, 1245, 1235, 1234. Sum(x) is defined as the sum of these substrings for a number x and the sequence above is those numbers such that sum(x) = x.

EXAMPLE

First term is 1729404 because sum(1729404) = 729404 + 129404 + 179404 + 172404 + 172904 + 172944 + 172940 = 1729404.

PROG

(PARI) isok(n) = {d = digits(n); if (sumdigits(n)*(#d-2) % 9 , return (0)); s = 0; for (i=1, #d, nd = vector(#d-1, j, if (i > j, d[j], d[j+1])); s += subst(Pol(nd), x, 10); ); s == n; } \\ Michel Marcus, Apr 24 2014

CROSSREFS

Cf. A093882.

Sequence in context: A157858 A157862 A186586 * A187139 A185844 A234130

Adjacent sequences:  A131636 A131637 A131638 * A131640 A131641 A131642

KEYWORD

base,easy,nonn

AUTHOR

Jon Ayres (jonathan.ayres(AT)ntlworld), Sep 05 2007

EXTENSIONS

a(12)-a(22) from Donovan Johnson, Jan 16 2011

a(23)-a(41) from Anthony Sand, Apr 24 2014

STATUS

approved

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Last modified December 18 07:25 EST 2014. Contains 252098 sequences.