A131517 Jazz chord substitution: Aminor,Cminor,DMajor,GMajor Uses a start vector based on these: {1, 4, 6, 11}.

1, 4, 8, 11, 4, 8, 11, 1, 8, 11, 1, 4, 11, 3, 6, 10, 4, 8, 11, 1, 8, 11, 1, 4, 11, 3, 6, 10, 1, 4, 8, 11, 8, 11, 1, 4, 11, 3, 6, 10, 1, 4, 8, 11, 4, 8, 11, 1, 11, 3, 6, 10, 3, 6, 10, 11, 6, 10, 1, 5, 10, 11, 3, 6, 4, 8, 11, 1, 8, 11, 1, 4, 11, 3, 6, 10, 1, 4, 8, 11, 8, 11, 1, 4, 11, 3, 6, 10, 1, 4

Offset

1,2

Comments

Actually a little more complex than most CGF chord type Jazz.

Links

Table of n, a(n) for n=1..90.

Formula

1-> {1, 4, 8, 11}; 2-> {2, 4, 7, 11}; 3-> {3, 6, 10, 11}; 4->{4, 8, 11, 1}; 5-> {5, 6, 10, 1}; 6-> {6, 10, 1, 5}; 7-> {7, 11, 12, 4}; 8->{8, 11, 1, 4}; 9-> {9, 1, 4, 8}; 10-> {10, 11, 3, 6}; 11->{11, 3, 6, 10}; 12->{12, 4, 7, 11};

Mathematica

Clear[s] s[1] = {1, 4, 8, 11}; s[2] = {2, 4, 7, 11}; s[3] = {3, 6, 10, 11}; s[4] = {4, 8, 11, 1}; s[5] = {5, 6, 10, 1}; s[6] = {6, 10, 1, 5}; s[7] = {7, 11, 12, 4}; s[8] = {8, 11, 1, 4}; s[9] = {9, 1, 4, 8}; s[ 10] = {10, 11, 3, 6}; s[11] = {11, 3, 6, 10}; s[12] = {12, 4, 7, 11}; t[a_] := Flatten[s /@ a]; p[0] = {1, 4, 6, 11}; p[1] = t[p[0]]; p[n_] := t[p[n - 1]]; p[3]

Crossrefs

Sequence in context: A293597 A131803 A133270 * A076689 A161867 A311011

Adjacent sequences: A131514 A131515 A131516 * A131518 A131519 A131520

Keyword

nonn,uned

Author

Roger L. Bagula, Oct 21 2007

Status

approved