

A131512


Iterated golden sieve : Iterate indefinitively the procedure giving A099267 (S2) from the natural numbers (S1) with the single difference that the rank of the deleted terms is f(n)+ (p2) to get Sp from Sp1.


0



2, 3, 6, 11, 18, 27, 39, 53, 69, 81, 87, 113, 141, 171, 204, 241, 277, 304, 336, 372, 410, 432, 442, 476, 512, 543, 592, 622, 657, 700, 739, 775, 808, 855, 897, 934, 984, 1021, 1069, 1106, 1155, 1199, 1247, 1297, 1341, 1388, 1440, 1490, 1538, 1592, 1640, 1686
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OFFSET

1,1


LINKS

Table of n, a(n) for n=1..52.


EXAMPLE

S1 =1,2,3,4,5,6,7,_,9,10,11,12,13,
S2 = A099267 =2,3,5,6,8,10,11,13,14,16,18
S3 : in S2 (32)+f(1)=3, then 5 is deleted, remaining 2,3,6,8,10,11,13,14,16,18
in this remaining sequence (32)+f(2)=4, then 8 is deleted, leaving 2,3,6,10,11,13,14,16,18
....
The two first terms of S2 are definitively safe. It's the same for the three first of S3, and so on;
Iterating indefinitely the procedure produces the sequence: 2,3,6,11,18,27,39,53,69,81,87,113 where the p first terms are already the p first terms of Sp and all following sequences.


CROSSREFS

Cf. A099267.
Sequence in context: A121617 A157656 A059100 * A147388 A180712 A273225
Adjacent sequences: A131509 A131510 A131511 * A131513 A131514 A131515


KEYWORD

easy,nonn


AUTHOR

Philippe LALLOUET (philip.lallouet(AT)wanadoo.fr), Aug 14 2007


STATUS

approved



