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A130909
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Simple periodic sequence (n mod 16).
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7
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0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
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OFFSET
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0,3
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COMMENTS
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The value of the rightmost digit in the base-16 representation of n. Also, the equivalent value of the two rightmost digits in the base-4 representation of n. Also, the equivalent value of the four rightmost digits in the base-2 representation of n.
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1).
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FORMULA
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a(n)=n mod 16 =n-16*floor(n/16). - G.f.: g(x)=(sum{1<=k<16, k*x^k})/(1-x^16). Also: g(x)=x(15x^16-16x^15+1)/((1-x^16)(1-x)^2).
a(n) = (1/2)*(15 - ( - 1)^n - 2*( - 1)^(b/4) - 4*( - 1)^((b - 2 + 2*( - 1)^(b/4))/8) - 8*( - 1)^((b - 6 + ( - 1)^n + 2*( - 1)^(b/4) + 4*( - 1)^((b - 2 + 2*( - 1)^(b/4))/8))/16)) where b = 2n - 1 + ( - 1)^n. - Hieronymus Fischer, Jun 14 2007
a(n)=n mod 2+2*(floor(n/2)mod 2)+4*(floor(n/4)mod 2)+8*(floor(n/8)mod 2). - Hieronymus Fischer, Jun 14 2007
a(n)=(1/2)*(15-(-1)^n-2*(-1)^floor(n/2)-4*(-1)^floor(n/4)-8*(-1)^floor(n/= 8)). - Hieronymus Fischer, Jun 14 2007
Complex representation: a(n)=(1/16)*(1-r^n)*sum{1<=k<16, k*product{1<=m<16,m<>k, (1-r^(n-m))}} where r=exp(pi/8*i)=(sqrt(2+sqrt(2))+i*sqrt(2-sqrt(2)))/2 and i=sqrt(-1). - Hieronymus Fischer, Jun 14 2007
Trigonometric representation: a(n)=2^22*(sin(n*pi/16))^2*sum{1<=k<16, k*product{1<=m<16,m<>k, (sin((n-m)*pi/16))^2}}. - Hieronymus Fischer, Jun 14 2007
a(n)=(1/2)*(15-(-1)^p(0,n)-2*(-1)^p(1,n)-4*(-1)^p(2,n)-8*(-1)^p(3,n)) where p(k,n) is defined recursively by p(0,n)=n, p(k,n)=1/4*(2*p(k-1,n)-1+(-1)^p(k-1,n)). - Hieronymus Fischer, Jun 14 2007
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PROG
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(Python)
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CROSSREFS
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See A010877 for a general formula in terms of powers of -1 (for period 2^k).
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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