|
|
A130680
|
|
Numbers n such that n = (a_1 + a_2 + ... + a_p)*(a_1^3 + a_2^3 + ... + a_p^3), where n has the decimal expansion a_1a_2...a_p.
|
|
9
|
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
This sequence is finite and all the terms are listed. Proof: Let a_1a_2...a_p be the decimal expansion of n. Then p <= log_10(n)+1. Furthermore we have a_i <= 9, therefore (a_1 + a_2 + ... + a_p) <= 9*(log_10(n)+1) and (a_1^3 + a_2^3 + ... + a_p^3) <= 9^3*(log_10(n)+1). On the other hand, for all n > 300000 we have 9^4*(log_10(n)+1)^2 < n. A computer search confirms that we indeed have found all terms.
|
|
LINKS
|
|
|
EXAMPLE
|
87949 = (8+7+9+4+9)*(8^3+7^3+9^3+4^3+9^3).
|
|
MATHEMATICA
|
For[n = 1, n < 1000000, n++, b = IntegerDigits[n]; If[Sum[b[[i]], {i, 1, Length[b]}] * Sum[b[[i]]^3, {i, 1, Length[b]}] == n, Print[n]]]
ffQ[n_]:=Module[{c=IntegerDigits[n]}, Total[c]Total[c^3]==n]; Select[ Range[ 90000], ffQ] (* Harvey P. Dale, Oct 18 2013 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
base,fini,full,nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|