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A130667
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a(1) = 1; a(n) = max{ 5*a(k) + a(n-k) | 1 <= k <= n/2 } for n > 1.
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11
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1, 6, 11, 36, 41, 66, 91, 216, 221, 246, 271, 396, 421, 546, 671, 1296, 1301, 1326, 1351, 1476, 1501, 1626, 1751, 2376, 2401, 2526, 2651, 3276, 3401, 4026, 4651, 7776, 7781, 7806, 7831, 7956, 7981, 8106, 8231, 8856, 8881, 9006, 9131, 9756, 9881, 10506, 11131
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OFFSET
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1,2
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COMMENTS
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The formula of Mar 26 2010 is equivalent to the following: Given the production matrix M below, lim_{k->infinity} M^k as a left-shifted vector generates the sequence.
1, 0, 0, 0, 0, ...
6, 0, 0, 0, 0, ...
5, 1, 0, 0, 0, ...
0, 6, 0, 0, 0, ...
0, 5, 1, 0, 0, ...
0, 0, 6, 0, 0, ...
0, 0, 5, 1, 0, ...
...
The sequence divided by its aerated variant is (1, 6, 5, 0, 0, 0, ...). (End)
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LINKS
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D. E. Knuth, Problem 11320, The American Mathematical Monthly, Vol. 114, No. 9 (Nov., 2007), p. 835.
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FORMULA
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a(2*n) = 6*a(n) and a(2*n+1) = 5*a(n) + a(n+1).
Let r(x) = (1 + 6*x + 5*x^2). Then (1 + 6*x + 11*x^2 + 36*x^3 + ...) = r(x) * r(x^2) * r(x^4) * r(x^8) * ... - Gary W. Adamson, Mar 26 2010
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MAPLE
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a:= proc(n) option remember;
`if`(n=1, 1, `if`(irem(n, 2, 'm')=0, 6*a(m), 5*a(m)+a(n-m)))
end:
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MATHEMATICA
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a[1]=1; a[n_] := a[n] = If[EvenQ[n], 6a[n/2], 5a[(n-1)/2]+a[(n+1)/2]]; Array[a, 50] (* Jean-François Alcover, Feb 13 2015 *)
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PROG
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(Haskell)
import Data.List (transpose)
a130667 n = a130667_list !! (n-1)
a130667_list = 1 : (concat $ transpose
[zipWith (+) vs a130667_list, zipWith (+) vs $ tail a130667_list])
where vs = map (* 5) a130667_list
(PARI) first(n)=my(v=vector(n), r, t); v[1]=1; for(i=2, n, r=0; for(k=1, i\2, t=5*v[k]+v[i-k]; if(t>r, r=t)); v[i]=r); v \\ Charles R Greathouse IV, Aug 29 2016
(Magma) [&+[5^(2*k - Valuation(Factorial(2*k), 2)): k in [0..n]]: n in [0..50]]; // Vincenzo Librandi, Mar 15 2019
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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