This is to Lucas numbers as A130150 is to Fibonacci numbers.
FORMULA
a(n) = A003617(A000032(n)) = (MIN{p(i) such that p(i) is prime and number of digits of decimal expansion of p(i) = L(n) for Lucas number L(n)} = MIN{A000040(i) such that A055642(A000040(i)) = A000032(n)}.
EXAMPLE
a(0) = 11 because L(0) = A000032(0) = 2 and 11 is the smallest 2 digit prime.
a(1) = 2 because L(1) = A000032(1) = 1 and 2 is the smallest 1 digit prime.
a(2) = 101 because L(2) = A000032(2) = 3 and 101 is the smallest 3 digit prime.
