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A128618
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Triangle read by rows: A128174 * A127647 as infinite lower triangular matrices.
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2
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1, 0, 1, 1, 0, 2, 0, 1, 0, 3, 1, 0, 2, 0, 5, 0, 1, 0, 3, 0, 8, 1, 0, 2, 0, 5, 0, 13, 0, 1, 0, 3, 0, 8, 0, 21, 1, 0, 2, 0, 5, 0, 13, 0, 34, 0, 1, 0, 3, 0, 8, 0, 21, 0, 55, 1, 0, 2, 0, 5, 0, 13, 0, 34, 0, 89, 0, 1, 0, 3, 0, 8, 0, 21, 0, 55, 0, 144, 1, 0, 2, 0, 5, 0, 13, 0, 34, 0, 89, 0, 233
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OFFSET
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1,6
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COMMENTS
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LINKS
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FORMULA
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By columns, Fibonacci(k) interspersed with alternate zeros in every column, k=1,2,3,...
Sum_{k=1..n} T(n, k) = A052952(n-1) (row sums).
T(n, k) = (1/2)*(1 + (-1)^(n+k))*Fibonacci(k).
T(2*n-1, n) = (1/2)*(1-(-1)^n)*A000045(n).
Sum_{k=1..n} (-1)^(k-1)*T(n, k) = (-1)^(n-1)*A052952(n-1).
Sum_{k=1..floor((n+1)/2)} T(n-k+1, k) = (1/2)*(1 - (-1)^n)*(Fibonacci((n+ 5)/2) - 1).
Sum_{k=1..floor((n+1)/2)} (-1)^(k-1)*T(n-k+1, k) = (1/2)*(1-(-1)^n) * A355020(floor((n-1)/2)). (End)
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EXAMPLE
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First few rows of the triangle are:
1;
0, 1;
1, 0, 2;
0, 1, 0, 3;
1, 0, 2, 0, 5;
0, 1, 0, 3, 0, 8;
1, 0, 2, 0, 5, 0, 13;
0, 1, 0, 3, 0, 8, 0, 21;
1, 0, 2, 0, 5, 0, 13, 0, 34;
0, 1, 0, 3, 0, 8, 0, 21, 0, 55;
1, 0, 2, 0, 5, 0, 13, 0, 34, 0, 89;
...
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MATHEMATICA
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Table[Fibonacci[k]*Mod[n-k+1, 2], {n, 15}, {k, n}]//Flatten (* G. C. Greubel, Mar 17 2024 *)
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PROG
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(Magma) [((n+k+1) mod 2)*Fibonacci(k): k in [1..n], n in [1..15]]; // G. C. Greubel, Mar 17 2024
(SageMath) flatten([[((n-k+1)%2)*fibonacci(k) for k in range(1, n+1)] for n in range(1, 16)]) # G. C. Greubel, Mar 17 2024
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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