%I #3 May 20 2014 14:52:32
%S 5,9,11,14,17,20,24,27,29,32,35,39,41,44,45,47,50,51,54,59,62,65,74,
%T 75,77,84,86,87,89,90,101,104,107,110,114,116,117,119,120,125,132,135,
%U 137,140,144,147,149,152,155,164,167,170,174,182,185,186,189,194,195,200
%N List of maximal breaks in generalized snooker.
%C Given A000217(R) red balls and C colored balls. For every red ball 1 point for it and C+1 points for the highest colored ball, followed by 2+3+4+... points for all colored balls. This sequence contains all numbers on the form A000217(R)*(C+2)+A000217(C+1)-1, R>0, C>0 (sorted, duplicates removed).
%e Let R=2 (1 point each) and C=3 (2, 3 and 4 (call that one black) points). The sequence red-black-red-black-red-black-2-3-black gives 24 points. Thus 24 is an element in this sequence.
%K nonn
%O 1,1
%A _Jonas Wallgren_, May 04 2007