%I #32 Dec 28 2021 17:27:24
%S 3,13,37,43,53,67,83,107,157,163,173,197,227,277,283,293,307,317,347,
%T 373,397,443,467,523,547,557,563,587,613,643,653,677,683,733,757,773,
%U 787,797,827,853,877,883,907,947,997,1013,1093,1117,1123,1163,1187,1213
%N a(n) = A023163(n)/3 for n > 1.
%C 3 divides A023163(n) for n > 1. A023163(n) are the numbers n such that Fibonacci(n) == -2 (mod n). Almost all terms of {a(n)} are prime that belong to A003631 = {2, 3, 7, 13, 17, 23, 37, 43, 47, 53, 67, 73, 83, 97} (primes congruent to {2, 3} mod 5) that are also the primes p that divide Fibonacci(p+1). The first composite term is a(74) = 1853 = 17*109. The second composite term is 9701 = 89*109. The third composite term is 10877 = 73*149 belong to A069107(n) Composite n such that n divides F(n+1) where F(k) are the Fibonacci numbers. Composite terms in {a(n)} are listed in A128289 = {1853, 9701, 10877, 17261, ...}.
%F a(n) = A023163(n)/3 for n > 1.
%e A023163 begins {1, 9, 39, 111, 129, 159, 201, 249, 321, 471, 489, 519, ...}.
%e Thus a(2) = A023163(2)/3 = 9/3 = 3, a(3) = A023163(3)/3 = 39/3 = 13.
%Y Cf. A002708, A023172, A023173, A023162, A023163 (numbers k such that Fibonacci(k) == -2 (mod k)).
%Y Cf. A003631, A069107, A128289 (composite terms in A128288).
%K nonn
%O 2,1
%A _Alexander Adamchuk_, Feb 24 2007