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Inverse Moebius transform of A128229.
2

%I #2 Mar 30 2012 17:25:19

%S 1,2,1,1,2,1,2,1,3,1,1,0,0,4,1,2,3,1,0,5,1,1,0,0,0,0,6,1,2,1,3,1,0,0,

%T 7,1,1,2,1,0,0,0,0,8,1,2,1,0,4,1,0,0,0,9,1

%N Inverse Moebius transform of A128229.

%C Row sums = sigma(n), A000203: (1, 3, 4, 7, 6, 12, 8,...) A128260 = A128229 * A051731

%F A051731 * A128229

%e First few rows of the triangle are:

%e 1;

%e 2, 1;

%e 1, 2, 1;

%e 2, 1, 3, 1;

%e 1, 0, 0, 4, 1;

%e 2, 3, 1, 0, 5, 1;

%e ...

%Y Cf. A128229, A051731, A000203, A128260.

%K nonn,tabl

%O 1,2

%A _Gary W. Adamson_, Feb 21 2007