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1, 0, 2, 1, 0, 3, 0, 2, 0, 4, 1, 0, 3, 0, 5, 0, 2, 0, 4, 0, 6, 1, 0, 3, 0, 5, 0, 7, 0, 2, 0, 4, 0, 6, 0, 8, 1, 0, 3, 0, 5, 0, 7, 0, 9, 0, 2, 0, 4, 0, 6, 0, 8, 0, 10
(list;
table;
graph;
refs;
listen;
history;
text;
internal format)
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OFFSET
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1,3
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COMMENTS
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Row sums = A002620: (1, 2, 4, 6, 9, 12, 16, 20, 25, 30, ...).
General case see A211161. Let B and C be sequences. By b(n) and c(n) denote elements B and C respectively. Table T(n,k) = b(n), if k is odd, c(k) if k is even read by antidiagonals. For this sequence b(n)=n, b(n)=A000027(n), c(n)=0, c(n)=A000004(n). - Boris Putievskiy, Feb 05 2013
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LINKS
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FORMULA
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A097807 * A002260 as infinite lower triangular matrices. k-th column = (k, 0, k, 0, ...).
T(n,k) = (1-(-1)^k)*n/2;
a(n) = (1-(-1)^j)*i/2, where i = n-t*(t+1)/2, j = (t*t+3*t+4)/2-n, t = floor((-1+sqrt(8*n-7))/2). (End)
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EXAMPLE
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The start of the sequence as a table:
1, 0, 1, 0, 1, 0, 1, ...
2, 0, 2, 0, 2, 0, 2, ...
3, 0, 3, 0, 3, 0, 3, ...
4, 0, 4, 0, 4, 0, 4, ...
5, 0, 5, 0, 5, 0, 5, ...
6, 0, 6, 0, 6, 0, 6, ...
7, 0, 7, 0, 7, 0, 7, ...
... (End)
First few rows of the triangle:
1;
0, 2;
1, 0, 3;
0, 2, 0, 4;
1, 0, 3, 0, 5;
0, 2, 0, 4, 0, 6;
1, 0, 3, 0, 5, 0, 7;
...
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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