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A127843 a(1) = 1, a(2) = ... = a(9) = 0, a(n) = a(n-9)+a(n-8) for n>9. 1

%I #24 Oct 08 2018 11:00:27

%S 1,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,1,0,0,0,0,0,0,1,2,1,0,0,0,0,0,1,

%T 3,3,1,0,0,0,0,1,4,6,4,1,0,0,0,1,5,10,10,5,1,0,0,1,6,15,20,15,6,1,0,1,

%U 7,21,35,35,21,7,1,1,8,28,56,70,56,28,8,2,9

%N a(1) = 1, a(2) = ... = a(9) = 0, a(n) = a(n-9)+a(n-8) for n>9.

%C Part of the phi_k family of sequences defined by a(1)=1, a(2)=...=a(k)=0, a(n)=a(n-k)+a(n-k+1) for n>k. phi_2 is a shift of the Fibonacci sequence and phi_3 is a shift of the Padovan sequence.

%C Apart from offset same as A017867. - _Georg Fischer_, Oct 07 2018

%D S. Suter, Binet-like formulas for recurrent sequences with characteristic equation x^k=x+1, preprint, 2007. [Apparently unpublished as of May 2016]

%H Colin Barker, <a href="/A127843/b127843.txt">Table of n, a(n) for n = 1..1000</a>

%H <a href="/index/Rec#order_09">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,1,1).

%F Binet-like formula: a(n) = Sum_{i=1..9} (r_i^n)/(8(r_i)^2+9(r_i)) where r_i is a root of x^9=x+1.

%F G.f.: x*(1-x)*(1+x)*(1+x^2)*(1+x^4) / (1-x^8-x^9). - _Colin Barker_, May 30 2016

%t LinearRecurrence[{0,0,0,0,0,0,0,1,1},{1,0,0,0,0,0,0,0,0},120] (* _Harvey P. Dale_, Jun 15 2017 *)

%t CoefficientList[Series[(1-x)*(1+x)*(1+x^2)*(1+x^4) / (1-x^8-x^9), {x, 0, 50}], x] (* _Stefano Spezia_, Oct 08 2018 *)

%o (PARI) Vec(x*(1-x)*(1+x)*(1+x^2)*(1+x^4)/(1-x^8-x^9) + O(x^100)) \\ _Colin Barker_, May 30 2016

%o (GAP) a:=[1,0,0,0,0,0,0,0,0];; for n in [10..90] do a[n]:=a[n-8]+a[n-9]; od; a; # _Muniru A Asiru_, Oct 07 2018

%K nonn,easy

%O 1,27

%A Stephen Suter (sms5064(AT)psu.edu), Apr 02 2007

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