%I #13 May 27 2019 17:20:34
%S 1,6,30,148,755,4044,22841,136056,853452,5625950,38885297,281170080,
%T 2122313505,16688829122,136457754030,1158155642512,10186602918035,
%U 92711977180164,871936904575985,8462913158427580,84668764368102012,872196382566014506,9241557859113581689
%N a(n) = (n+1) * A005493(n).
%C A127740 = (n+1) * each term in Aitken's triangle, A011971.
%C A127741 = row sums of A127740.
%H Chai Wah Wu, <a href="/A127741/b127741.txt">Table of n, a(n) for n = 0..250</a>
%F a(n) = (n+1) * A005493(n), where A005493 = row sums of Aitken's triangle: (1, 3, 10, 37, ...); i.e., 1*1, 2*3, 3*10, 4*37, ... Row sums of A127740.
%e a(n) = sum of terms in n-th row of A127740. a(2) = 30 = (6 + 9 + 15).
%o (Python)
%o # requires Python 3.2 or higher. Otherwise use def'n of accumulate in Python docs.
%o from itertools import accumulate
%o A127741_list, blist, b = [], [1], 1
%o for n in range(1,1001):
%o ....blist = list(accumulate([b]+blist))
%o ....b = blist[-1]
%o ....A127741_list.append(blist[-2]*n) # _Chai Wah Wu_, Sep 20 2014
%Y Cf. A000110, A052889, A011971, A127740.
%K nonn
%O 0,2
%A _Gary W. Adamson_, Jan 27 2007
%E Edited by _Jon E. Schoenfield_, May 27 2019